Contents
Changelog:
- 7 October 2020: Adjust description of “stalling for
halt
” to mention idea of changing howf_pc
is set. - 8 October 2020: Strongly deemphasize mention of the idea of forwarding to the beginning of the execute stage as a suggested approach for forwarding to be more consistent with our textbook and lecture.
Your task
- In a file called
pipehw1.hcl
, implement a five-stage pipelined Y86 processor (using the pipeline stages described in the textbook) that includes these instructions and uses forwarding to resolve hazards:nop
halt
irmovq
rrmovq
OPq
, andcmovXX
(Implement all five stages even though no instructions use the memory stage.)
You will probably start with your pipelab1 implementation (which includes
nop
,halt
,irmovq
, andrrmovq
, but with only two stages). -
Test your implementation with
make test-pipehw1
. - Submit your
pipehw1.hcl
to kytos.
Hints/Approach
General Approach
-
Get to know and love figure 4.41 (page 424 of the 3rd edition, page 403 of the 2nd). To match the textbook’s text, the name of these registers would be
fF
,fD
,dE
,eM
, andmW
. -
We prefer to not add all the registers to each register bank in advance, instead adding them as needed for the instructions you implement.
Stalling for halt
You will only need one pipeline stall for this homework: if the Stat
computed during Fetch is not STAT_AOK
, you need to prevent
additional instructions from being fetched. One way to do this is to adjust the logic that sets f_pc
. Another is to stall the register bank feeding the fetch stage.
Note that you’ll need to pass that non-OK Stat
down through all the pipeline registers before putting it into the Stat
output, so
this will require 4 cycles during which new instructions are not fetched
When you extend this processor to handle memory instructions, this stall will help you ensure that a program like:
irmovq $10, %rax
halt
rmmovq %rax, 10(%rax)
does not write a value to memory, and otherwise prevent changing the state of your processor because of logically unexecuted instructions.
Forwarding
For these instructions, rrmovq
and OPq
read a register but either irmovq
or rrmovq
or OPq
could be writing it.
One approach, suggested by our textbook and similar to what you did in pipelab1, is to add a mux to the inputs d_valA
and d_valB
to the dE
register (like most students do
for pipelab1) that checks for things like
reg_srcA == m_dstE : m_valE;
and so on for all the other possible overlaps of src
s and dst
s that are later in the pipeline.
(Another approach would be to add a MUX before the ALU inputs (replacing direct uses of E_valA
and E_valB
), checking for things like:
E_srcA == M_dstE : M_valE;
and so on for all the other possible overlaps of src
s and dst
s that are later in the pipeline, and
to separately handle forwarding values from writeback to decode.)
OPq
and condition codes
-
Put the condition codes in their own register bank; you don’t want to bubble them if you bubble another register bank as part of stalling a stage.
-
Check the condition codes in execute (based on the
ifun
there) and store the result of that comparison in theeM
register bank. This will be helpful later when you implementjXX
.
cmovXX
and condition codes
To implement cmovXX
, all you need to do is change reg_dstE
to be either the value you’d normally predict for it or REG_NONE
, depending on the truth of the condition codes. The easiest way to do that is probably by adding a mux in the execute stage, something like
e_dstE = [
/* this is a cmovXX and the condition codes are not satisfied */ : REG_NONE;
1 : E_dstE;
];
Orgranizing your code
You may either put all your registers at the beginning of the file, or you may put them between the phases in question. The hclrs
executable makes multiple passes through your file, so defining them after you use them is permitted and can lead to a more flow-oriented layout, but some people find that distracting and prefer to define before use. Whichever you prefer.
Specific test cases
Here, we hilight test cases for specific functionality. A common strategy is to get these test cases working in order, then proceed to more complete testing of the processor.
nop
and halt
and illegal instructions
The following program (y86/halt.yo
)
halt
should take 5 cycles to complete and do nothing (fetching address 0x0 four times and updating no registers or memory)
The following program (y86/nophalt.yo
)
nop
nop
nop
halt
nop
should take 8 cycles to complete and do nothing (fetching address 0x0, 0x1, 0x2, and then 0x3 five times (never fetch address 0x4) and update no registers or memory)
The following program (y86/ins.yo
)
nop
iaddq $1, %r8
halt
should take 6 cycles to complete, do nothing, and end with an invalid instruction error (error code 4, STAT_INS
)
irmovq
and rrmovq
The following program (y86/irrr7.yo
)
irmovq $1, %rax
rrmovq %rax, %rbx
should take 7 cycles to complete and leave 1 in both %rax
and %rbx
.
The following program (y86/rrmovq.yo
)
irmovq $5678, %rax
irmovq $34, %rcx
rrmovq %rax, %rdx
rrmovq %rcx, %rax
should take 9 cycles to complete and change the following registers:
| RAX: 22 RCX: 22 RDX: 162e |
The following program (y86/irrr7b.yo
)
irmovq $0x1, %rax
irmovq $0x2, %rbx
irmovq $0x3, %rcx
rrmovq %rax, %rdx
rrmovq %rcx, %rbx
rrmovq %rbx, %rsi
rrmovq %rbx, %rdi
should take 12 cycles and change the following registers:
| RAX: 1 RCX: 3 RDX: 1 |
| RBX: 3 RSP: 0 RBP: 0 |
| RSI: 3 RDI: 3 R8: 0 |
OPq
The following program (y86/opq.yo
)
irmovq $7, %rdx
irmovq $3, %rcx
addq %rcx, %rbx
subq %rdx, %rcx
andq %rdx, %rbx
xorq %rcx, %rdx
andq %rdx, %rsi
should take 12 cycles and leave
| RAX: 0 RCX: fffffffffffffffc RDX: fffffffffffffffb |
| RBX: 3 RSP: 0 RBP: 0 |
A full trace is in testdata/pipe-traces/opq.txt
.
The programs y86/forward1a.yo
through y86/forward4a.yo
and
y86/forward1b.yo
through y86/forward4b.yo
systematically test forwarding
cases involving irmovq
and OPq
.
cmovXX
The following program (y86/cmovXX.yo
)
irmovq $2766, %rbx
irmovq $1, %rax
andq %rax, %rax
cmovg %rbx, %rcx
cmovne %rbx, %rdx
irmovq $-1, %rax
andq %rax, %rax
cmovl %rbx, %rsp
cmovle %rbx, %rbp
xorq %rax, %rax
cmove %rbx, %rsi
cmovge %rbx, %rdi
irmovq $2989, %rbx
irmovq $1, %rax
andq %rax, %rax
cmovl %rbx, %rcx
cmove %rbx, %rdx
irmovq $-1, %rax
andq %rax, %rax
cmovge %rbx, %rsp
cmovg %rbx, %rbp
xorq %rax, %rax
cmovl %rbx, %rsi
cmovne %rbx, %rdi
irmovq $0, %rbx
should take 30 cycles and leave 0xace
in %rcx
, %rdx
, %rsp
, %rbp
, %rsi
, and %rdi
.
A full trace is available in testdata/pipe-traces/cmovXX.txt
.
Other tests
make test-pipehw1
also runs the following tests, which overlap substantially with
the above tests:
prog1.yo
throughprog4.yo
andprog8.yo
cmov-noforward.yo
irmovq-norcxrax.yo
Debugging
Our general advice for debugging this assignment:
- Use the values of the pipeline registers to figure out which instruction is in each pipeline stage;
- Redirect
hclrs
output to a text file and open it up in a text editor; - Use the
-d
output; - Write out what instruction is in each stage of the pipeline;
- Try to simplify the test cases so it’s easier to spot your problems;